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Home » You Won’t Believe What Willam Bumpus Did Next—Unsigned! - GetMeFoodie

You Won’t Believe What Willam Bumpus Did Next—Unsigned! - GetMeFoodie

📅 May 1, 2026 👤 scraface

May 01, 2026

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= z^3 + \left(\frac{-407}{3}\right)z + \left(\frac{512 - 1536 + 648 -...
= z^3 - \frac{407}{3}z - \frac{158}{3}
Diskriminante eines kubischen \( z^3 + pz + q \): \( \Delta = -4p^3 -...
Hier: \( p = -\frac{407}{3} \), \( q = -\frac{158}{3} \)
\Delta = -4\left(-\frac{407}{3}\right)^3 - 27\left(-\frac{158}{3}\righ...
Besser: positives Vorzeichen:
\( -4p^3 = -4 \cdot \left( -\frac{407^3}{27} \right) = \frac{4}{27} \c...
\( 27q^2 = 27 \cdot \frac{24964}{9} = 3 \cdot 24964 = 74892 \)
But \( p \) is large negative denominator: \( p = -\frac{407}{3} \Righ...
\( q^2 = \left(\frac{158}{3}\right)^2 = \frac{24964}{9} \), so \( 27q^...

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