From \( -y = x \) and \( x = y \), substituting: \( -x = x \Rightarrow x = 0 \), then \( y = 0 \). Only solution is \(\mathbf{v} = egin{pmatrix} 0 \ 0 \end{pmatrix}\), but \( \|\mathbf{v}\|^2 = 0

Thu, 30 Apr 2026 14:09:29 +0000

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