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Home » So $ f $ is additive. Also, from the multiplicative condition: - GetMeFoodie

So $ f $ is additive. Also, from the multiplicative condition: - GetMeFoodie

📅 May 1, 2026 👤 scraface

May 01, 2026

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\cos \phi = rac{z}{
ho}, \quad ext{so} \quad
ho = rac{4}{2 + rac{z}{
Multiply both sides by $ 2 + rac{z}{
ho} $:
ho \left(2 + rac{z}{
ight) = 4 \Rightarrow 2
ho + z = 4 \Rightarrow 2
ho = 4 - z.
Now substitute $

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