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Let $r = \sqrt{x^2 + y^2}$. Then:
r^2 + z^2 = 4r \Rightarrow r^2 - 4r + z^2 = 0 \Rightarrow (r - 2)^2 + z^2 = 4
This is a sphere of radius 2 centered at $(2, 0, 0)$ in cylindrical coordinates, which corresponds to a **sphere tangent to the y-z plane** in Cartesian coordinates.

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