**Perhaps in the Sum, $ k Indexes, and $ (4-k) Is Horizontal Pairs Per Row—But Only If Rows Are Labeled k:
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📰 $2730 \cdot 109 = 2730 \cdot (100 + 9) = 273000 + 24570 = 297,570$
📰 Wait — correction: in earlier computation, we had $4 \cdot 3 \cdot 5 \cdot 7 \cdot 17 \cdot 119$, but $119 = 7 \cdot 17$, and $119$ has repeated factor 7, so $7^1$ is sufficient.
📰 But $1,2,3,5,7,13,109$: all distinct primes → LCM = product of all distinct prime factors = $2 \cdot 3 \cdot 5 \cdot 7 \cdot 13 \cdot 109$
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