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how long is influenza a contagious - GetMeFoodie

📅 May 1, 2026 👤 scraface

May 01, 2026

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📌 R \cos\alpha = 1, \quad R \sin\alpha = \sqrt{3}

📌 R^2 = 1^2 + (\sqrt{3})^2 = 4 \Rightarrow R = 2

📌 \cos\alpha = \frac{1}{2}, \quad \sin\alpha = \frac{\sqrt{3}}{2} \Rightarrow \alpha = 60^\circ

📌 So the equation becomes:

📌 \sin(2z + 60^\circ) = 1 \Rightarrow \sin(2z + 60^\circ) = \frac{1}{2}

📌 The general solution for $ \sin \theta = \frac{1}{2} $ is:

📌 \theta = 30^\circ + 360^\circ k \quad \text{or} \quad \theta = 150^\circ + 360^\circ k

📌 Let $ \theta = 2z + 60^\circ $, so:

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