C(2) = (2)^3 - 3(2)^2 + 2(2) = 8 - 12 + 4 = 0

Understanding the Polynomial Identity: C(2) = (2)³ – 3(2)² + 2(2) = 0

When encountering the equation
C(2) = (2)³ – 3(2)² + 2(2),
at first glance, it may appear merely as a computation. However, this expression reveals a deeper insight into polynomial evaluation and combinatorial mathematics—particularly through its result equaling zero. In this article, we’ll explore what this identity represents, how it connects to binomial coefficients, and why evaluating such expressions at specific values, like x = 2, matters in both symbolic computation and real-world applications.

Understanding the Context

What Does C(2) Represent?

At first, the symbol C(2) leads some to question its meaning—unlike standard binomial coefficients denoted as C(n, k) (read as “n choose k”), which count combinations, C(2) by itself lacks a subscript k, meaning it typically appears in algebraic expressions as a direct evaluation rather than a combinatorial term. However, in this context, it functions as a polynomial expression in variable x, redefined as (2)³ – 3(2)² + 2(2).

This substitution transforms C(2) into a concrete numerical value—specifically, 0—when x is replaced by 2.

2 + 2 + 3 + 4 11 "2 + 2 + 3 + 4 "2 + 2 34" 2 + 3 + 4 | Chegg.com

Image Gallery

Solved A = [1 2 3 2 1 4], B = [1 0 2 1 3 2] C = [3 -1 3 | Chegg.com

[ANSWERED] 2 2 3 18 A 0 C 9 2 B 11 2 D 10 2 4 2 54 3 3 2 3 A 6 6 6 3 B ...

Solved 3 3 - 2 0 -2 2 If A= - 2 2 - 2 BE 4 4 -2. and AB=C = | Chegg.com

Key Insights

Evaluating the Polynomial: Step-by-Step

Let’s carefully compute step-by-step:

Start with:
C(2) = (2)³ – 3(2)² + 2(2)
Compute each term:
- (2)³ = 8
- 3(2)² = 3 × 4 = 12
- 2(2) = 4
Plug in values:
C(2) = 8 – 12 + 4

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Final Thoughts

Simplify:
8 – 12 = –4, then
–4 + 4 = 0

Thus, indeed:
C(2) = 0

Is This a Binomial Expansion?

The structure (2)³ – 3(2)² + 2(2) closely resembles the expanded form of a binomial expression, specifically the expansion of (x – 1)³ evaluated at x = 2. Let’s recall:
(x – 1)³ = x³ – 3x² + 3x – 1

Set x = 2:
(2 – 1)³ = 1³ = 1
But expanding:
(2)³ – 3(2)² + 3(2) – 1 = 8 – 12 + 6 – 1 = 1

Our expression:
(2)³ – 3(2)² + 2(2) = 8 – 12 + 4 = 0 ≠ 1

So while similar in form, C(2) is not the full expansion of (x – 1)³. However, notice the signs and coefficients:

The signs alternate: +, –, +
Coefficients: 1, –3, +2 — unlike the symmetric ±1 pattern in binomials.

This suggests C(2) may be a special evaluation of a polynomial related to roots, symmetry, or perhaps a generating function.