A rectangle has a perimeter of 60 cm. Its length is twice its width. Find the area of the rectangle. - GetMeFoodie

Understanding the Context

With the US seeing rising interest in smart space solutions and efficient design, this geometric problem sits at the intersection of education and real-world application, resonating with users who value accuracy without complexity.

Why This Rectangle Problem Is Winning Attention

Perimeter, length, and width relationships are fundamental geometry concepts—still central in home improvement, interior design, and manufacturing. Recent digital trends show growing interest in point solutions: quick, digestible fixes for common questions, especially those tied to interior planning, renovation budgeting, and product specifications.

Key Insights

The idea that a rectangle has a 60 cm perimeter with length twice the width combines concrete numbers with a familiar shape, making it easy to relate to. Mobile users scanning for quick answers or learning new concepts appreciate this balance of simplicity and relevance—key for engageable content in a snappy format like Discover.

This problem also taps into user intent around precision and planning, aligning with those actively researching perfect room dimensions, cost estimates, or DIY project layouts.

How to Calculate the Area Without Overcomplicating Math

Start by defining the rectangle’s dimensions using the perimeter and length-to-width ratio. Let the width be w. Then the length is 2w.

Final Thoughts

A rectangle’s perimeter formula is:
Perimeter = 2 × (length + width)

Plugging in the known values:
60 = 2 × (2w + w)
60 = 2 × 3w
60 = 6w

Dividing both sides by 6 gives:
w = 10 cm

Since the length is twice the width:
length = 2 × 10 = 20 cm

Now calculate the